5 Best Ways to Compare Lists of Dictionaries in Python

πŸ’‘ Problem Formulation: In Python, comparing lists of dictionaries is a common task that data scientists and developers encounter. Given two lists of dictionaries, the goal might be to find out if they contain the same dictionaries (regardless of order), or if they hold identical data structure and values. For example, you might want to compare the following input: [{'id': 1, 'value': 'apple'}, {'id': 2, 'value': 'orange'}] with [{'id': 2, 'value': 'orange'}, {'id': 1, 'value': 'apple'}] to determine if they are equivalent despite the change in order.

Method 1: Using a Loop and Comparing Keys and Values

This method involves iterating through the lists of dictionaries and comparing key-value pairs individually. It is most useful when you need to determine if two lists contain the exact same dictionaries, including the same order.

Here’s an example:

def compare_lists_of_dicts(lst1, lst2):
    if len(lst1) != len(lst2):
        return False
    for dict1, dict2 in zip(lst1, lst2):
        if dict1 != dict2:
            return False
    return True

# Usage
result = compare_lists_of_dicts(
    [{'id': 1, 'value': 'apple'}],
    [{'id': 1, 'value': 'apple'}]
)
print(result)

Output: True

This function compare_lists_of_dicts() returns True if both lists contain the same dictionaries in the same order. It pairs dictionaries from the two lists using the built-in zip() function, then compares each pair for equality.

Method 2: Using the All Function and Sorted Method

For unordered comparison, the all() function combined with sorted method can be used to verify that all the dictionaries in one list are contained in another list, and vice versa. It works well for order-independent comparison scenarios.

Here’s an example:

def unordered_compare(lst1, lst2):
    return all(any(d1 == d2 for d2 in lst2) for d1 in lst1) and all(any(d1 == d2 for d2 in lst1) for d1 in lst2)

# Usage
result = unordered_compare(
    [{'id': 1, 'value': 'apple'}, {'id': 2, 'value': 'orange'}],
    [{'id': 2, 'value': 'orange'}, {'id': 1, 'value': 'apple'}]
)
print(result)

Output: True

This snippet uses list comprehensions with the any() and all() functions to verify that for every dictionary in one list, there is an equal dictionary in the other list. Note that this method has a quadratic time complexity and might not be efficient for large lists.

Method 3: Using a Custom Hash Function

By generating a hash for each dictionary within the lists that represents its contents uniquely, you can compare these hashes for a quick and efficient comparison. This works best when dictionaries contain hashable types.

Here’s an example:

def hash_dict(d):
    return hash(frozenset(d.items()))

def compare_by_hash(lst1, lst2):
    hashed1 = {hash_dict(d) for d in lst1}
    hashed2 = {hash_dict(d) for d in lst2}
    return hashed1 == hashed2

# Usage
result = compare_by_hash(
    [{'id': 1, 'value': 'apple'}],
    [{'id': 1, 'value': 'apple'}]
)
print(result)

Output: True

In this method, a hash function hash_dict() creates a frozenset of the dictionary items before hashing, ensuring that the resulting hash is independent of the order of items within the dictionaries. The sets of hashes are then compared for equality.

Method 4: Using Deep Equality with deepcopy()

Deep equality can be checked by making a deep copy of the dictionaries within the lists and then comparing them. This method ensures that the actual content is compared rather than references or orders of keys.

Here’s an example:

import copy

def deep_equal(lst1, lst2):
    return copy.deepcopy(lst1) == copy.deepcopy(lst2)

# Usage
result = deep_equal(
    [{'id': 1, 'value': 'apple'}],
    [{'id': 1, 'value': 'apple'}]
)
print(result)

Output: True

This code uses Python’s copy.deepcopy() to create completely independent copies of the lists, which are then compared using the standard equality operator. This method is convenient for nested dictionaries or dictionaries containing lists but can be less efficient for large or deeply nested structures.

Bonus One-Liner Method 5: Using JSON

If serialization is acceptable, converting dictionaries to a JSON string and then comparing those strings can be a succinct method for comparing dictionaries. JSON serialization naturally handles unordered keys within dictionaries.

Here’s an example:

import json

def compare_json(lst1, lst2):
    return json.dumps(lst1, sort_keys=True) == json.dumps(lst2, sort_keys=True)

# Usage
result = compare_json(
    [{'id': 1, 'value': 'apple'}],
    [{'id': 1, 'value': 'apple'}]
)
print(result)

Output: True

This function compare_json() uses json.dumps() with the sort_keys parameter set to True, ensuring the dictionaries are serialized in a consistent order, allowing for a straightforward string comparison.

Summary/Discussion

  • Method 1: Loop and Compare Keys and Values. Best for ordered list comparisons. Can be slow for large lists due to O(n) complexity.
  • Method 2: All Function and Sorted Method. Useful for unordered comparisons. Not suitable for large lists due to O(n^2) complexity.
  • Method 3: Custom Hash Function. Efficient for large and unordered lists. Limited to hashable types within dictionaries.
  • Method 4: Deep Equality with deepcopy(). Suited for nested structures. Inefficient for large or deeply nested data.
  • Bonus Method 5: Using JSON Serialization. Quick and clean for simple dictionaries. Serialization overhead can be a drawback.