5 Best Ways to Convert a Python List of Dicts to a Single Dict

πŸ’‘ Problem Formulation: How do we merge a list of dictionaries in Python into a single dictionary? This task is common when dealing with lists of configuration options or data records. Imagine we have a list [{"a": 1}, {"b": 2}, {"c": 3}] and we want to combine it into one dictionary {"a": 1, "b": 2, "c": 3}. This article presents various methods to achieve this in Python.

Method 1: Using a For Loop

The for loop is one of the most straightforward methods to merge a list of dictionaries. It iterates through each dictionary in the list and updates a new dictionary with the key-value pairs from each.

Here’s an example:

merged_dict = {}
dicts_list = [{"a": 1}, {"b": 2}, {"c": 3}]
for d in dicts_list:
    merged_dict.update(d)

The output will be:

{'a': 1, 'b': 2, 'c': 3}

This code snippet initializes an empty dictionary called merged_dict and iteratively updates it with the key-value pairs from each dictionary in the list dicts_list. The update() method is used for merging.

Method 2: Using the dict() Constructor and itertools.chain()

The dict() constructor can convert a sequence of key-value tuples into a dictionary. By pairing it with itertools.chain(), you can flatten the list of dictionaries and then transform it into the resulting single dictionary.

Here’s an example:

from itertools import chain
dicts_list = [{"a": 1}, {"b": 2}, {"c": 3}]
merged_dict = dict(chain.from_iterable(d.items() for d in dicts_list))

The output will be:

{'a': 1, 'b': 2, 'c': 3}

Here, chain.from_iterable() is used to create an iterator that goes over all the key-value pairs in each dictionary in our list, effectively flattening them. The dict() constructor then takes this iterator and creates a single dictionary.

Method 3: Using Dictionary Comprehension

Dictionary comprehension is a concise and pythonic way to create dictionaries. It can also be used to merge a list of dictionaries by extracting all pairs from each dictionary and combining them into a new one.

Here’s an example:

dicts_list = [{"a": 1}, {"b": 2}, {"c": 3}]
merged_dict = {k: v for d in dicts_list for k, v in d.items()}

The output will be:

{'a': 1, 'b': 2, 'c': 3}

This code snippet employs dictionary comprehension to iterate over each dictionary and then over each key-value pair within that dictionary, effectively merging all dictionaries into merged_dict.

Method 4: Using the ** Operator in a Dictionary Comprehension

The ** operator is often used to unpack dictionary arguments in function calls. It can also be used within a dictionary comprehension to merge a list of dictionaries.

Here’s an example:

dicts_list = [{"a": 1}, {"b": 2}, {"c": 3}]
merged_dict = {k: v for d in dicts_list for k, v in {**d}.items()}

The output will be:

{'a': 1, 'b': 2, 'c': 3}

This code snippet takes advantage of the ** operator to unpack each dictionary in the list within the dictionary comprehension, creating a single merged dictionary.

Bonus One-Liner Method 5: Using functools.reduce() and operator.concat()

For those who prefer functional programming paradigms, the functools.reduce() function can be utilized along with operator.concat() to merge a list of dictionaries in a concise one-liner.

Here’s an example:

from functools import reduce
import operator
dicts_list = [{"a": 1}, {"b": 2}, {"c": 3}]
merged_dict = reduce(operator.iconcat, (d.items() for d in dicts_list), ())
merged_dict = dict(merged_dict)

The output will be:

{'a': 1, 'b': 2, 'c': 3}

This snippet uses reduce() to apply the iconcat() function cumulatively to the items of each dictionary, starting with an empty tuple and converting the resulting flattened list of tuples back to a dictionary.

Summary/Discussion

  • Method 1: Using a For Loop. It’s simple and easy to understand. Inefficient for a large number of dictionaries due to repeated calls to update().
  • Method 2: Using the dict() Constructor and itertools.chain(). More efficient for large lists of dictionaries. Requires importing an additional module.
  • Method 3: Using Dictionary Comprehension. Pythonic and concise. Output depends on the order of dictionaries in the list and may cause conflicts if there are overlapping keys.
  • Method 4: Using the ** Operator in a Dictionary Comprehension. One-liner and readable. It’s essentially a variation of Method 3 with a different syntax.
  • Method 5: Using functools.reduce() and operator.concat(). A functional approach that’s elegant but may be less intuitive for those who don’t regularly use functional programming paradigms.