π‘ Problem Formulation: Finding multiples of a number is a common mathematical task, but what if we’re interested in multiples with exactly two digits? In Python, we want to write programs that will return multiples of a given number n
, such that the multiples have only two digits. For instance, if the input is 5
, the desired output could be 10
, 15
, 20
, etc.
Method 1: Iterative Search
This method involves iterating through a range of two-digit numbers and checking if the number is a multiple of n
. This is simple and straightforward, and it doesn’t require any advanced mathematical operations or modules.
Here’s an example:
def find_two_digit_multiples(n): result = [] for i in range(10, 100): if i % n == 0: result.append(i) return result multiples = find_two_digit_multiples(7) print(multiples)
Output:
[14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98]
This code snippet creates a function called find_two_digit_multiples()
that takes an integer n
and returns a list of its multiples between 10 and 99 (the range of two-digit numbers). The function iterates through this range, using the modulo operator to check for multiples, and appends them to the result list.
Method 2: List Comprehension
List comprehensions in Python provide a concise way to create lists. We can use them to filter out the two-digit multiples of n
in a single line of code.
Here’s an example:
def find_two_digit_multiples(n): return [i for i in range(10, 100) if i % n == 0] multiples = find_two_digit_multiples(8) print(multiples)
Output:
[16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96]
The find_two_digit_multiples()
function uses a list comprehension to generate a list of multiples of n
within the two-digit range. The condition inside the list comprehension ensures that only true multiples are included.
Method 3: Using a While Loop
A while loop can be used to continuously find multiples of n
and stop as soon as the number exceeds two digits. This method can be more efficient than iterating through an entire fixed range.
Here’s an example:
def find_two_digit_multiples(n): result = [] multiple = n while 10 <= multiple < 100: result.append(multiple) multiple += n return result multiples = find_two_digit_multiples(9) print(multiples)
Output:
[18, 27, 36, 45, 54, 63, 72, 81, 90, 99]
The find_two_digit_multiples()
function initializes a multiple to n
and uses a while loop to append successively larger multiples to a list. The loop runs until the multiple is no longer a two-digit number.
Method 4: Using Math and Range
We can mathematically determine the start and end points for our search, ensuring we only look at two-digit numbers. This approach minimizes the number of iterations.
Here’s an example:
def find_two_digit_multiples(n): start = (10 // n) * n if start < 10: start += n end = (100 // n) * n return list(range(start, end, n)) multiples = find_two_digit_multiples(4) print(multiples)
Output:
[12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96]
This code snippet calculates the smallest and largest two-digit multiples of n
and then uses range()
to generate the list of all multiples between them. This is both concise and efficient.
Bonus One-Liner Method 5: Using Generators
We can write an elegant one-liner using a generator expression. This approach offers lazy evaluation, which can save memory if the list of multiples is large.
Here’s an example:
find_two_digit_multiples = lambda n: (i for i in range(10, 100) if i % n == 0) multiples = list(find_two_digit_multiples(3)) print(multiples)
Output:
[12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99]
A lambda function is used to create a generator that yields two-digit multiples of n
. When we want to retrieve the multiples, we convert the generator into a list.
Summary/Discussion
- Method 1: Iterative Search. Simple to understand and implement. May be inefficient for large ranges or small values of n.
- Method 2: List Comprehension. Concise and pythonic. Can be slightly less readable for beginners.
- Method 3: Using a While Loop. Provides control over the iteration process. Efficiency depends on the value of n.
- Method 4: Using Math and Range. Mathematically precise and efficient with no unnecessary iterations. Slightly more complex to understand.
- Method 5: Using Generators. Memory efficient and elegant. Lazy evaluation can be more complex for beginners to understand.