**π‘ Problem Formulation:** Imagine you have an array and you need to find the minimum distance between any position of a target element and a specified starting index. For example, given an array `[1, 2, 3, 2, 2, 5]`

and target element `2`

, with a starting index of `2`

, the minimum distance to the target element is `0`

because the target is at the starting index itself.

## Method 1: Linear Search

The linear search approach involves iterating over the array from the starting index and checking each element until we find the target. Once we locate the target, we can compute the distance from the starting index. It’s simple and straightforward but not the most efficient for large arrays.

Here’s an example:

def linear_search(arr, target, start): for i in range(start, len(arr)): if arr[i] == target: return abs(i - start) return -1 # Example usage: arr = [1, 2, 3, 2, 2, 5] target = 2 start = 2 print(linear_search(arr, target, start))

Output: `0`

This code snippet defines a function `linear_search`

that starts from the given index and iterates through the array to find the first occurrence of the target element, returning the distance to it or `-1`

if the target is not found.

## Method 2: Using Enumerate with List Comprehension

This approach combines the power of list comprehensions with the enumerate function to create a list of distances where the target appears. We then return the minimum of these distances. This method is more Pythonic but can use more memory due to list creation.

Here’s an example:

def enumerate_search(arr, target, start): distances = [abs(i - start) for i, v in enumerate(arr) if v == target] return min(distances) if distances else -1 # Example usage: arr = [1, 2, 3, 2, 2, 5] target = 2 start = 2 print(enumerate_search(arr, target, start))

Output: `0`

The `enumerate_search`

function uses list comprehension and `enumerate`

to find all indices where the target is found, calculates their distances to the start index, and returns the smallest distance, ensuring a concise and efficient search.

## Method 3: Using the filter and map functions

This approach leverages the `filter`

and `map`

functions to create a more functional programming style. We filter the enumerated pairs of indices and values, then map to distances and find the minimum. This approach is elegant but a bit harder to read for those unfamiliar with functional programming paradigms.

Here’s an example:

def filter_map_search(arr, target, start): indices = map(lambda x: x[0], filter(lambda iv: iv[1] == target, enumerate(arr))) distances = map(lambda i: abs(i - start), indices) return min(distances) if distances else -1 # Example usage: arr = [1, 2, 3, 2, 2, 5] target = 2 start = 2 print(filter_map_search(arr, target, start))

Output: `0`

The function `filter_map_search`

first isolates indices where the target appears using `filter`

and `enumerate`

, calculates distances with `map`

, and finally returns the minimum distance.

## Method 4: Using NumPy for Large Datasets

If the dataset is large, we can use NumPy to efficiently compute distances. NumPy’s array operations are optimized for performance, and the library itself offers methods like `np.where`

that can be beneficial. However, this adds a dependency on an external library and is more suited for numerical computations.

Here’s an example:

import numpy as np def numpy_search(arr, target, start): arr = np.array(arr) indices = np.where(arr == target)[0] distances = np.abs(indices - start) return np.min(distances) if len(distances) > 0 else -1 # Example usage: arr = [1, 2, 3, 2, 2, 5] target = 2 start = 2 print(numpy_search(arr, target, start))

Output: `0`

Here, the `numpy_search`

function leverages NumPy’s array operations to find target indices, compute distances, and return the minimum. It’s great for performance but does require understanding of numpy arrays.

## Bonus One-Liner Method 5: Using Python’s min with a generator expression

In this one-liner approach, we use Python’s built-in `min`

function with a generator expression to create a concise expression that solves the problem without building a list. It’s memory-efficient and Pythonic.

Here’s an example:

arr = [1, 2, 3, 2, 2, 5] target = 2 start = 2 print(min((abs(i - start) for i, v in enumerate(arr) if v == target), default=-1))

Output: `0`

This one-liner makes use of a generator expression within the `min`

function to find the minimum distance directly. It doesn’t store intermediate results, making it very efficient for memory usage while still being relatively easy to read.

## Summary/Discussion

**Method 1: Linear Search.**Easy to understand and implement. Can be slow for large arrays as it traverses the entire list.**Method 2: Enumerate with List Comprehension.**More Pythonic and compact than Method 1. However, it creates an intermediate list, which could be memory-intensive.**Method 3: Using filter and map functions.**Offers a functional programming approach. This can be less clear for readers not comfortable with functional programming concepts.**Method 4: Using NumPy for Large Datasets.**Highly efficient for large datasets and performance-critical applications. Requires an external library and familiarity with NumPy.**Bonus Method 5: One-Liner with Generator Expression.**Memory-efficient, Pythonic, and very compact, but may not be as fast as the numpy method for very large datasets.