π‘ Problem Formulation: Finding local extrema in an array involves identifying points where a value is greater than its neighbors (a local maximum) or less than them (a local minimum). Given an array of integers, such as [2, 3, 1, 5, 4]
, the goal is to count the number of local extrema. The desired output would be 2
, corresponding to the values 3
and 5
.
Method 1: Iterative Comparison
This method implies iterating over the array and comparing each element with its adjacent values to find the local maxima and minima. It assumes the array is not cyclic and that the first and last elements can’t be local extrema unless there are additional comparisons for edge cases.
Here’s an example:
def count_local_extrema(arr): count = 0 for i in range(1, len(arr) - 1): if arr[i] > arr[i - 1] and arr[i] > arr[i + 1] or arr[i] < arr[i - 1] and arr[i] < arr[i + 1]: count += 1 return count print(count_local_extrema([2, 3, 1, 5, 4]))
Output:
2
This code function count_local_extrema()
takes an array as input and proceeds to count the number of local extrema. The count increases when an element is greater or smaller than both neighbors, validating both local minima and maxima.
Method 2: Utilizing NumPy Library
Using the NumPy library, one can employ array operations to locate local extrema. This method is efficient for large datasets and exploits the speed of vectorized operations in NumPy.
Here’s an example:
import numpy as np def count_local_extrema(arr): arr = np.asarray(arr) gradient = np.diff(arr) extrema = np.diff((gradient > 0).view(np.int8)) return np.count_nonzero(extrema == -1) + np.count_nonzero(extrema == 1) print(count_local_extrema([2, 3, 1, 5, 4]))
Output:
2
The count_local_extrema()
function converts the input list to a NumPy array and computes its first discrete difference. Then, it finds local extrema using the sign changes in the difference, summing up the instances of sign changes indicating local maxima and minima.
Method 3: Using List Comprehensions
This method leverages the conciseness of list comprehensions to compare adjacent values. It is a Pythonic approach that combines readability with efficiency, suitable for smaller datasets.
Here’s an example:
def count_local_extrema(arr): return sum([1 for i in range(1, len(arr) - 1) if arr[i] > arr[i - 1] and arr[i] > arr[i + 1] or arr[i] < arr[i - 1] and arr[i] < arr[i + 1]]) print(count_local_extrema([2, 3, 1, 5, 4]))
Output:
2
The count_local_extrema()
function is a one-liner that builds a list of 1
‘s for each local extremum using a list comprehension, and then sums the list to provide the total count.
Method 4: Using Itertools Chain Function
The itertools library’s chain function can be employed to handle potential local extrema at the boundaries. This method is invaluable for those who want full control over edge cases and the start and end of datasets.
Here’s an example:
from itertools import chain def count_local_extrema(arr): count = 0 arr = list(chain([float('inf')], arr, [float('inf')])) for i in range(1, len(arr) - 1): if arr[i] > arr[i - 1] and arr[i] > arr[i + 1] or arr[i] < arr[i - 1] and arr[i] < arr[i + 1]: count += 1 return count print(count_local_extrema([2, 3, 1, 5, 4]))
Output:
2
By expanding the array with float('inf')
on either side, the count_local_extrema()
function can handle boundary conditions as extrema. The subsequent logic is similar to Method 1 but includes first and last elements in the count if they are extrema.
Bonus One-Liner Method 5: Using Enumerate and Slicing
A compact one-liner approach uses enumerate and slicing to iterate over the array efficiently. It is suitable for those who prefer minimalistic and ingenious Python solutions.
Here’s an example:
def count_local_extrema(arr): return sum(1 for i, val in enumerate(arr[1:-1], 1) if val > arr[i - 1] and val > arr[i + 1] or val < arr[i - 1] and val < arr[i + 1]) print(count_local_extrema([2, 3, 1, 5, 4]))
Output:
2
The function count_local_extrema()
employs a generator expression along with enumerate()
which offsets the starting index by 1, facilitating the comparison of each element with its previous and next counterparts. The enumeration skips the first and last array elements.
Summary/Discussion
- Method 1: Iterative Comparison. Simple and straightforward. Works well with small datasets. Not the most efficient with large datasets.
- Method 2: Utilizing NumPy. Great for large datasets due to NumPy’s optimized operations. However, it adds a library dependency.
- Method 3: List Comprehensions. Pythonic and concise, easy to read. Might not be the most performant for very large arrays.
- Method 4: Using Itertools. Versatile handling of edge cases. Somewhat more complex and less concise than other methods.
- Method 5: One-Liner with Enumerate. Very Pythonic and compact. This approach sacrifices a bit of clarity for succinctness.