5 Efficient Ways to Sort a List of Dictionaries by the Sum of Their Values in Python

πŸ’‘ Problem Formulation: We often encounter the need to organize complex data structures in Python, such as a list of dictionaries. The task is to sort this list based not on a single value or key, but on the cumulative sum of the values within each dictionary. Given the input [{'a': 5, 'b': 15}, {'a': 3, 'b': 4, 'c': 2}], the desired output after sorting would be [{'a': 3, 'b': 4, 'c': 2}, {'a': 5, 'b': 15}], since 3+4+2 = 9 which is less than 5+15 = 20.

Method 1: Using a Custom Sort Key Function

This method involves using Python’s sorted() function with a custom key function that calculates the sum of the dictionary’s values. The sorted() function then sorts the list based on this computed sum for each dictionary, providing an efficient way to order the dictionaries as per our requirement.

Here’s an example:

data_list = [{'a': 5, 'b': 15}, {'a': 3, 'b': 4, 'c': 2}]
sorted_list = sorted(data_list, key=lambda x: sum(x.values()))
print(sorted_list)

The Output:

[{'a': 3, 'b': 4, 'c': 2}, {'a': 5, 'b': 15}]

This code snippet defines a lambda function as the sorting key, which ensures that the sorted() function sorts the dictionaries based on the sum of their values. As expected, the dictionary with the smallest sum comes first in the sorted list.

Method 2: In-Place Sorting with list.sort()

Instead of creating a new sorted list, the list.sort() method sorts the list of dictionaries in-place. It works similarly to the sorted() function but modifies the original list directly. This approach is memory-efficient as it does not create an additional list.

Here’s an example:

data_list = [{'a': 5, 'b': 15}, {'a': 3, 'b': 4, 'c': 2}]
data_list.sort(key=lambda x: sum(x.values()))
print(data_list)

The Output:

[{'a': 3, 'b': 4, 'c': 2}, {'a': 5, 'b': 15}]

In this example, the original data_list is sorted in-place. The lambda function used in the key parameter plays the same role as in the first method, guiding the sort function to organize the dictionaries by their values’ sum.

Method 3: Using the Operator Module

This method takes advantage of the itemgetter function from Python’s operator module, along with the map function, to extract and sum values before sorting. This method is favorable for readability and efficiency in some cases, especially with pre-existing complex sort keys.

Here’s an example:

from operator import itemgetter
data_list = [{'a': 5, 'b': 15}, {'a': 3, 'b': 4, 'c': 2}]
sorted_list = sorted(data_list, key=lambda d: sum(map(itemgetter(1), d.items())))
print(sorted_list)

The Output:

[{'a': 3, 'b': 4, 'c': 2}, {'a': 5, 'b': 15}]

Using the operator.itemgetter function, this snippet extracts the values of each dictionary, sums them up and then sorts the list according to the resulting sums. Although it is slightly more verbose, this method is sometimes faster than using a lambda function.

Method 4: Using List Comprehension

With list comprehension, you can create a list of tuples where the first element is the sum of dictionary values, and the second element is the dictionary itself. Sorting this list of tuples naturally orders the dictionaries by the sum of their values.

Here’s an example:

data_list = [{'a': 5, 'b': 15}, {'a': 3, 'b': 4, 'c': 2}]
sorted_list = sorted([(sum(d.values()), d) for d in data_list])
print([d for s, d in sorted_list])

The Output:

[{'a': 3, 'b': 4, 'c': 2}, {'a': 5, 'b': 15}]

This snippet sorts a newly created list of tuples, with each tuple containing the sum and the respective dictionary. The second print statement is used to extract and display only the dictionaries from the sorted tuples, in the correct order.

Bonus One-Liner Method 5: Using a Generator Expression

One-liners in Python are often appreciated for their compactness. Here’s how to sort the list using a generator expression within the sorted() function. It’s a condensed version of the list comprehension approach and very Pythonic.

Here’s an example:

data_list = [{'a': 5, 'b': 15}, {'a': 3, 'b': 4, 'c': 2}]
sorted_list = sorted(data_list, key=lambda d: sum(val for val in d.values()))
print(sorted_list)

The Output:

[{'a': 3, 'b': 4, 'c': 2}, {'a': 5, 'b': 15}]

This code employs a generator expression to sum up the dictionary values directly within the key argument of the sorted() function, providing a neat and concise solution.

Summary/Discussion

  • Method 1: Custom Sort Key Function. It’s straightforward and concise. May not be the fastest for complex sort keys.
  • Method 2: In-Place Sorting. Memory efficient as no new list is created. Not suitable if you need to preserve the original list order.
  • Method 3: Using the Operator Module. Good for complex sorting keys and usually faster than simple lambda methods.
  • Method 4: Using List Comprehension. Helps visualize the sorting process. It’s a bit complex and creates an intermediate list of tuples.
  • Bonus Method 5: Generator Expression One-Liner. It’s elegant and perfect for Pythonists who love one-liners. Can be slightly harder to understand for beginners.