The Most Pythonic Way to Get N Largest and Smallest List Elements
Using heapq.nlargest() and heapq.nsmallest() is more efficient than sorting the entire list and then slicing it. Sorting takes O(n log n) time and slicing takes O(N) time, making the overall time complexity O(n log n) + O(N). However, heapq.nlargest() and heapq.nsmallest() have a time complexity of O(n log N), which is more efficient, especially when … Read more