Given a string in the octal form:
s = '0o77' # or s = '77'
How to convert the octal string to an integer in Python?
For example, you want to convert the octal string
'o10' to the decimal integer
Here are a few other examples:
Oct String to Integer using int() with Base 8
To convert an octal string to an integer, pass the string as a first argument into Python’s built-in
int() function. Use
base=8 as a second argument of the
int() function to specify that the given string is an octal number. The
int() function will then convert the octal string to an integer with base 10 and return the result.
Here’s a minimal example:
>>> int('0o77', base=8) 63
And here’s how you can convert the additional examples shown above:
>>> int('0o0', base=8) 0 >>> int('0o4', base=8) 4 >>> int('0o10', base=8) 8 >>> int('0o14', base=8) 12 >>> int('0o20', base=8) 16 >>> int('0o77', base=8) 63 >>> int('0o77777', base=8) 32767
You actually don’t need to use the prefix
'0o' because your second argument already defines unambiguously that the given string is an octal number:
>>> int('0', base=8) 0 >>> int('4', base=8) 4 >>> int('10', base=8) 8 >>> int('14', base=8) 12 >>> int('20', base=8) 16 >>> int('77', base=8) 63 >>> int('77777', base=8) 32767
However, skipping the base but leaving the prefix raises a
ValueError: invalid literal for int() with base 10: '0o77':
>>> int('0o77') Traceback (most recent call last): File "<pyshell#16>", line 1, in <module> int('0o77') ValueError: invalid literal for int() with base 10: '0o77'
It assumes that the input string is in base 10 when in fact, it isn’t.
💡 Note: Even though passing a prefixed string
'0o...' into the
int() function is unambiguous, Python’s
int() function doesn’t accept it if you don’t also define the base. This may be fixed in future versions!
In fact, you can specify the base argument as
0 to switch on base guessing—which should be the default behavior anyway! 👇
You can pass a prefixed string
'0o...' into the
int() function and set the base to
0 to switch on base guessing in Python. This uses the prefix to determine the base automatically—without you needing to set it to
16. Yet, you still have to set it to
0 so the benefit is marginal in practice.
>>> int('0o7', base=8) 7 >>> int('0o7', base=0) 7 >>> int('0o7', 0) 7
Converting Octal Literals to Int
If you don’t have an octal string but a octal number—called a literal—such as
0xff, you don’t even need the
int() function because Python will automatically convert it to a decimal number:
>>> 0o743 483 >>> 0o7 7 >>> 0o10 8
int(value [, base]) --> int
|Argument||A Python object to be converted into an integer number. The value object must have an |
|An optional integer argument |
|Return Value||Returns an integer number after converting the input argument |
Do you still need more background information about Python’s built-in
int() function? No problem, read over the related tutorial.
🌍 Related Tutorial: Python’s Built-in
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