Problem Formulation and Solution Overview
Biogenix, a Lab Supplies company, needs to determine the best element from the Periodic Table for producing a new product. They have two (2) lists. The Element Name, the other Atomic Mass. They would prefer this in a Dictionary format.
For simplicity, this article uses 10 of the 118 elements in the Periodic Table.
π¬ Question: How would we create a Dictionary from two (2) Lists?
We can accomplish this task by one of the following options:
- Method 1: Use
dict()
andzip()
- Method 2: Use Dictionary Comprehension
- Method 3: Use Generator Expression with
dict()
andzip()
- Method 4: Use Lambda
Method 1: Use dict() and zip()
This method uses zip()
to merge two (2) lists into an iterable object and (dict()
) to convert it into a Dictionary as key:value pairs.
el_name = ['Meitnerium', 'Darmstadtium', 'Roentgenium', 'Copernicium', 'Nihonium', 'Flerovium', 'Moscovium', 'Livermorium', 'Tennessine', 'Oganesson'] el_atom = [277.154, 282.166, 282.169, 286.179, 286.182, 290.192, 290.196, 293.205, 294.211, 295.216] merge_lists = zip(el_name, el_atom) new_dict = dict(merge_lists) for k, v in new_dict.items(): print ("{:<20} {:<15}".format(k, v))
- Lines [1-2] create two (2) lists containing the Element Name (
el_name
) and corresponding Atomic Mass (el_atom
), respectively. - Line [3] merges the two (2) lists using
zip()
and converts them into an iterable object. The results save tomerge_lists
. - Line [4] converts
merge_lists
into a Dictionary (dict())
. The results save tonew_dict
as key:value pairs. - Line [5] instantiates a For loop to return the key:value pairs from
new_dict
.- Each iteration outputs the key:value pair in a column format to the terminal.
Code (snippet)
Meitnerium | 277.154 |
Darmstadtium | 282.166 |
Roentgenium | 282.169 |
Copernicium | 286.179 |
Nihonium | 286.182 |
Method 2: Use Dictionary Comprehension
This method uses Dictionary Comprehension to merge two (2) lists into an iterable object and convert it into a Dictionary as key:value pairs. A great one-liner!
el_name = ['Meitnerium', 'Darmstadtium', 'Roentgenium', 'Copernicium', 'Nihonium', 'Flerovium', 'Moscovium', 'Livermorium', 'Tennessine', 'Oganesson'] el_atom = [277.154, 282.166, 282.169, 286.179, 286.182, 290.192, 290.196, 293.205, 294.211, 295.216] new_dict = {el_name[i]: el_atom[i] for i in range(len(el_name))} for k, v in new_dict.items(): print ("{:<20} {:<15}".format(k, v))
- Lines [1-2] create two (2) lists containing the Element Name (
el_name
) and the corresponding Atomic Mass (el_atom
), respectively. - Line [3] merges the lists as key:value pairs and converts them into a Dictionary. The results save to
new_dict
. - Line [4] instantiates a For loop to return the key:value pairs from
new_dict
.- Each iteration outputs the key:value pair in a column format to the terminal.
Code (snippet)
Meitnerium | 277.154 |
Darmstadtium | 282.166 |
Roentgenium | 282.169 |
Copernicium | 286.179 |
Nihonium | 286.182 |
Method 3: Use Generator Expression with zip() and dict()
This method uses a Generator Expression to merge two (2) lists into an iterable object (zip()
) and convert it into a Dictionary (dict()
) as key:value pairs.
el_name = ['Meitnerium', 'Darmstadtium', 'Roentgenium', 'Copernicium', 'Nihonium', 'Flerovium', 'Moscovium', 'Livermorium', 'Tennessine', 'Oganesson'] el_atom = [277.154, 282.166, 282.169, 286.179, 286.182, 290.192, 290.196, 293.205, 294.211, 295.216] gen_exp = dict(((k, v) for k, v in zip(el_name, el_atom))) for k, v in new_dict.items(): print ("{:<20} {:<15}".format(k, v))
- Lines [1-2] create two (2) lists containing the Element Name (
el_name
) and the corresponding Atomic Mass (el_atom
) respectively. - Line [3] uses a Generator Expression to merge the lists (
zip()
) and create an iterable object. The object converts into a Dictionary (dict()
) and saves back togen_exp
. - Line [5] instantiates a For loop to return the key:value pairs from
new_dict
.- Each iteration outputs the key:value pair in a column format to the terminal.
Code (snippet)
Meitnerium | 277.154 |
Darmstadtium | 282.166 |
Roentgenium | 282.169 |
Copernicium | 286.179 |
Nihonium | 286.182 |
Method 4: Use a Lambda
This method uses a Lambda to merge two (2) lists into an iterable object (zip()
) and convert it into a Dictionary (dict()
) as key:value pairs.
el_name = ['Meitnerium', 'Darmstadtium', 'Roentgenium', 'Copernicium', 'Nihonium', 'Flerovium', 'Moscovium', 'Livermorium', 'Tennessine', 'Oganesson'] el_atom = [277.154, 282.166, 282.169, 286.179, 286.182, 290.192, 290.196, 293.205, 294.211, 295.216] new_dict = dict((lambda n, a: {name: el_atom for name, el_atom in zip(n, a)})(el_name, el_atom)) for k, v in new_dict.items(): print ("{:<20} {:<15}".format(k, v))
- Lines [1-2] create two (2) lists containing the Element Name (
el_name
) and the corresponding Atomic Mass (el_atom
) respectively. - Line [3] uses a lambda to merge the lists (
zip()
) and create an iterable object. The results save to a Dictionarynew_dict
as key:value pairs. - Line [4] instantiates a For loop to return the key:value pairs from
new_dict
.- Each iteration outputs the key:value pair in a column format to the terminal.
Code (snippet)
Meitnerium | 277.154 |
Darmstadtium | 282.166 |
Roentgenium | 282.169 |
Copernicium | 286.179 |
Nihonium | 286.182 |
Summary
After reviewing the above methods, we decide that Method 2 is best suited: minimal overhead and no additional functions required.
Problem Solved! Happy Coding!