Can you spot the outliers in the following sequence: 000000001000000001? Detecting outliers fast can be mission critical for many applications in military, air transport, and energy production.

This article shows you the most basic outlier detection algorithm: * if an observed value deviates from the mean by more than the standard deviation, it is considered an outlier. * You can also watch the explainer video here:

## What is an Outlier Anyways?

First, letâs study what exactly is an outlier. In this article, we make the basic assumption that all observed data is normally distributed around a mean value. For example, consider the following sequence:

[ 8.78087409 10.95890859 8.90183201 8.42516116 9.26643393 12.52747974 9.70413087 10.09101284 9.90002825 10.15149208 9.42468412 11.36732294 9.5603904 9.80945055 10.15792838 10.13521324 11.0435137 10.06329581 ... 10.74304416 10.47904781]

If you plot this sequence, youâll get the following figure:

Here’s the code used to generate this plot:

import numpy as np import matplotlib.pyplot as plt sequence = np.random.normal(10.0, 1.0, 500) print(sequence) plt.xkcd() plt.hist(sequence) plt.annotate(r"$\omega_1=9$", (9, 70)) plt.annotate(r"$\omega_2=11$", (11, 70)) plt.annotate(r"$\mu=10$", (10, 90)) plt.savefig("plot.jpg") plt.show()

The sequence seems to resemble a normal distribution with a mean value of 10 and a standard deviation of 1.

The mean is the average value of all sequence values.

The standard deviation is the deviation from the mean so that approximately 68% of all sample values are lying within the standard deviation interval.

In the following, we simply assume that *any observed value that is outside of the interval marked by the standard deviation around the mean is an outlier*.

## Method 1: Detect Outliers in Website Analytics (One-Liner)

Imagine you are the administrator of an online application and you need to analyze the website traffic on a continuous basis. As the administrator of the Python web application Finxter.com, this is one of my daily activities.

This one-liner examines the following problem: *âFind all outlier days which statistics (columns) deviate more than the standard deviation from their mean statisticsâ*

## Dependencies import numpy as np ## Website analytics data: ## (row = day), (col = users, bounce, duration) a = np.array([[815, 70, 115], [767, 80, 50], [912, 74, 77], [554, 88, 70], [1008, 65, 128]]) mean, stdev = np.mean(a, axis=0), np.std(a, axis=0) # Mean: [811.2 76.4 88. ] # Std: [152.97764543 6.85857128 29.04479299] ## Find Outliers outliers = ((np.abs(a[:,0] - mean[0]) > stdev[0]) * (np.abs(a[:,1] - mean[1]) > stdev[1]) * (np.abs(a[:,2] - mean[2]) > stdev[2])) ## Result print(a[outliers])

The data set consists of multiple rows and columns. Each row comprises daily statistics consisting of three columns (daily active users, bounce rate, and average session duration in seconds).

For each column (statistically tracked metric), we calculate the mean value and the standard deviation. For example, the mean value of the âdaily active usersâ column is 811.2 and its standard deviation is 152.97. Note that we use the axis argument to calculate the mean and standard deviation of each column separately.

Recall that our goal is to detect outliers. But how to do this for our website analytics? The code simply assumes that every observed value that does not fall within the standard deviation around the mean of each specific column is an outlier. Itâs that simple.

For example, the average value of the âdaily active usersâ column is 811.2 and its standard deviation is 152.97. Thus, every observed value for the âdaily active usersâ metric that is smaller than 811.2-152.97=658.23 or larger than 811.2+152.23=963.43 is considered an outlier for this column.

However, we consider a day to be an outlier only if all three observed columns are outliers. Itâs easy to achieve this by combining the three Boolean arrays using the âlogical andâ operation of NumPy. The logical and can be replaced with a simple multiplication scheme as True is represented by an integer 1 and False by an integer 0.

We use `np.abs()`

in the code snippet that simply converts the negative values in a NumPy array into their positive counterparts.

This article is based on my book—I’ll show you the next method to detect outliers in a moment.

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## Method 2: IQR

This method from this GitHub code base uses the Interquartile range to remove outliers from the data x. This excellent video from Khan Academy explains the idea quickly and effectively:

The following code snippet remove outliers using NumPy:

import numpy as np def removeOutliers(x, outlierConstant): a = np.array(x) upper_quartile = np.percentile(a, 75) lower_quartile = np.percentile(a, 25) IQR = (upper_quartile - lower_quartile) * outlierConstant quartileSet = (lower_quartile - IQR, upper_quartile + IQR) resultList = [] for y in a.tolist(): if y >= quartileSet[0] and y <= quartileSet[1]: resultList.append(y) return resultList

## Method 3: Remove Outliers From NumPy Array Using np.mean() and np.std()

This method is based on the useful code snippet provided here.

To remove an outlier from a NumPy array, use these five basic steps:

- Create an array with outliers
- Determine mean and standard deviation
- Normalize array around 0
- Define the maximum number of standard deviations
- Access only non-outliers using Boolean Indexing

import numpy as np # 1. Create an array with outliers a = np.array([1, 1, 1, 1, 1, 1, 42, 1, 1]) # 2. Determine mean and standard deviation mean = np.mean(a) std_dev = np.std(a) # 3. Normalize array around 0 zero_based = abs(a - mean) # 4. Define maximum number of standard deviations max_deviations = 2 # 5. Access only non-outliers using Boolean Indexing no_outliers = a[zero_based < max_deviations * std_dev] print(no_outliers) # [1 1 1 1 1 1 1 1]

## Where to Go From Here?

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While working as a researcher in distributed systems, Dr. Christian Mayer found his love for teaching computer science students.

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His passions are writing, reading, and coding. But his greatest passion is to serve aspiring coders through Finxter and help them to boost their skills. You can join his free email academy here.