# How to Find the Minimum of a List of Lists in Python?

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Short answer: To find the minimal list in a list of lists, you need to make two lists comparable. How? With the `key` argument of the `min()` function. The key argument is a function that takes one input (a list) and returns one output (a numerical value). The list with the smallest numerical value is returned as the minimum of the list of lists.

Problem: Say you have a list of lists (nested list) and you want to find the minimum of this list. It’s not trivial to compare lists—what’s the minimum among lists after all? To define the minimum among the inner lists, you may want to consider different objectives.

1. The first element of each inner list.
2. The i-th element of each inner list.
3. The sum of inner list elements.
4. The maximum of inner list elements.
5. The minimum of inner list elements.

Example: Given list of lists `[[1, 1, 1], [0, 2, 0], [3, 3, -1]]`. Which is the minimum element?

1. The first element of each inner list. The minimum is `[0, 2, 0]`.
2. The i-th element of each inner list (`i = 2`). The minimum is `[3, 3, -1]`.
3. The sum of inner list elements. The minimum is `[0, 2, 0]`.
4. The maximum of inner list elements. The minimum is `[1, 1, 1]`.
5. The minimum of inner list elements. The minimum is `[3, 3, -1]`.

So how do you accomplish this?

Solution: Use the `min()` function with key argument.

Syntax: The `min()` function is a built-in function in Python (Python versions 2.x and 3.x). Here’s the syntax:

`min(iterable, key=None)`

Arguments:

Let’s study the solution code for our different versions of calculating the minimal “list” of a list of lists (nested list).

Try it yourself in our interactive code shell:

```lst = [[1, 1, 1], [0, 2, 0], [3, 3, -1]]

# Minimum using first element
print(min(lst, key=lambda x: x[0]))
# [0, 2, 0]

# Minimum using third element
print(min(lst, key=lambda x: x[2]))
# [3, 3, -1]

# Minimum using sum()
print(min(lst, key=sum))
# [0, 2, 0]

# Minimum using max
print(min(lst, key=max))
# [1, 1, 1]

# Minimum using min
print(min(lst, key=min))
# [3, 3, -1]
```

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