Problem Formulation
Given a Python list and an element (value). How to remove the element (value) from the given list?
Here’s an example of what you want to accomplish:
- Given:
- List
[1, 2, 99, 4, 99]
- Element
99
- List
- Return:
- List
[1, 2, 4, 99]
- List
An alternative would return the list with the element (value) 99
removed in all occurrences:
- Return:
- List
[1, 2, 4]
- List
We’ll first look at the first problem variant in Method 1 and then examine the second in Method 2.
Method 1: list.remove()
>>> lst = [1, 2, 99, 4, 99] >>> lst.remove(99) >>> lst [1, 2, 4, 99]
In the first line of the example, you create the list lst
. You then remove the integer element 99 from the list—but only its first occurrence. The result is the list with only four elements [1, 2, 4, 99]
.
Syntax:
You can call this method on each list object in Python. Here’s the syntax:
Arguments:
Argument | Description |
---|---|
element | Object you want to remove from the list. Only the first occurrence of the element is removed. |
Return value:
The method list.remove(element)
has return value None
. It operates on an existing list and, therefore, doesn’t return a new list with the removed element
Video:
You can also check out our full blog tutorial on the Python list.remove()
method.
Removed Element Does Not Exist
Let’s have a look at another example where this fails next!
To remove an element from the list, use the list.remove(element)
method you’ve already seen previously:
>>> lst = ["Alice", 3, "alice", "Ann", 42] >>> lst.remove("Ann") >>> lst ['Alice', 3, 'alice', 42]
The method goes from left to right and removes the first occurrence of the element that’s equal to the one to be removed.
If you’re trying to remove element x
from the list but x
does not exist in the list, Python raises a ValueError
:
>>> lst = ['Alice', 'Bob', 'Ann'] >>> lst.remove('Frank') Traceback (most recent call last): File "<pyshell#19>", line 1, in <module> lst.remove('Frank') ValueError: list.remove(x): x not in list
To fix this, you can enclose it in a try/except environment like so:
lst = ['Alice', 'Bob', 'Ann'] try: lst.remove('Frank') except: pass print('done!')
This code goes through and returns 'done!'
without any error message.
Method 2: Python List remove() All
The list.remove(x)
method only removes the first occurrence of element x
from the list.
But what if you want to remove all occurrences of element x
from a given list?
The answer is to use a simple loop:
lst = ['Ann', 'Ann', 'Ann', 'Alice', 'Ann', 'Bob'] x = 'Ann' while x in lst: lst.remove(x) print(lst) # ['Alice', 'Bob']
You simply call the remove()
method again and again until element x
is not in the list anymore.
For comprehensibility, I want to show you one method that is not optimal—but that’s recommended all over the web (e.g., here).
Method 3: List Comprehension: Remove Elements Conditionally
Using list comprehension is cheating because this method does not really remove elements from a list object. It merely creates a new list with some elements that meet your condition.
List comprehension is a compact way of creating lists. The simple formula is:
[ expression + context ]
- Expression: What to do with each list element?
- Context: What list elements to select? It consists of an arbitrary number of for and if statements.
The example [x for x in range(3)]
creates the list [0, 1, 2]
.
You can also define a condition such as “all values unlike a given element 1”, e.g., x!=1
, in the context part by using an if
condition.
This leads us to a way to remove all elements that are equal to a certain value such as our value 99
in a given list.
>>> lst = [1, 2, 99, 4, 99] >>> lst_new = [x for x in lst if x != 99] >>> lst_new [1, 2, 4]
While you iterate over the whole list lst
, you include only the elements that are not equal to the element 99
. Thus, the resulting list has all elements 99
removed.
However, the original list lst
has not changed!
>>> lst [1, 2, 99, 4, 99]
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Where to Go From Here?
Enough theory. Let’s get some practice!
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