- Given string
How to remove all characters in
s after the first occurrence of
Given: - string s = 'hello world', and - empty space character c = ' '. Desired result: 'hello'
Method 1: string.index() + slicing
To remove everything after the first occurrence of character
c, determine the index of
s.index(c). Then pass the result as stop index into a slicing operation, starting from the first character such as in
s[:s.index(c)]. The result is the substring up to the first occurrence of character
# Method 1: string.index() + slicing s = 'hello world' c = ' ' result = s[:s.index(c)] print(result) # hello
Method 2: string.split()
str.split(sep, maxsplit) with
maxsplit set to
1 splits the string into two substrings into a list. It splits the string at the first occurrence of the separator argument
sep. By accessing the first element of this list, you obtain the string with everything before the first occurrence of the
# Method 2: string.split() s = 'hello world' c = ' ' result = s.split(c, 1) print(result) # hello
string.split(delimiter, maxsplit=1) method creates a list of strings, split at the delimiter string. If you split at delimiter character
c, the first element of the split list is the string before the first occurrence of character
c. That’s why the operation
s.split(c, 1) gives you the string with everything removed after the first occurrence of the character
Method 3: Regex
re.findall(pattern, string) method of Python’s regular expression library
re creates a list of strings that match the
pattern in the given
string. By using the pattern
'.*' + c, you match everything up to the first occurrence of the character
c. You take the first element of the returned list with the indexing operation
... and determine all characters but the last one (that is the matching character
c) by using slicing
...[:-1] up to the second last element.
# Method 3: regex import re s = 'hello world' c = ' ' result = re.findall('.*' + c, s)[:-1] print(result) # hello
Where to Go From Here?
Enough theory, let’s get some practice!
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