Python’s *in-place bitwise right-shift operator*`x >>= y`

calculates the right-shift operation `x >> y`

, and assigns the result to the first operands variable name `x`

. You can set up the in-place right-shift behavior in your own class by overriding the magic “dunder” method `__irshift__(self, other)`

in your class definition.

>>> x = 8 >>> x >>= 2 >>> x 2

The expression `x >>= y`

is syntactical sugar for the longer-form `x = x >> y`

:

>>> x = 8 >>> x = x >> 2 >>> x 2

Let’s explore some examples on different data types of the operands.

## Recap Bitwise Right-Shift

The Python ** bitwise right-shift** operator

`x >> n`

shifts the binary representation of integer `x`

by `n`

positions to the right. It inserts a `0`

bit on the left and removes the right-most bit. For example, if you right-shift the binary representation `0101`

by one position, you’d obtain `0010`

. Semantically, the bitwise right-shift operator is the same as performing integer division by `2**n`

.Here’s a minimal example:

print(8 >> 1) # 4 print(8 >> 2) # 2 print(-3 >> 1) # -2

Here’s a short explainer video too:

**Related. **To learn more about the bitwise right-shift operator, and how it works on positive and negative integers, check out our related tutorial: > Operator”>Python Bitwise Right-Shift Operator

## Incompatible Data Type

What if two operands have an incompatible data type—unlike floats and integers? For example, if you try to shift a float variable by a list variable (which doesn’t make sense)?

>>> x = 3.0 >>> y = [1, 2] >>> x >> y Traceback (most recent call last): File "<pyshell#5>", line 1, in <module> x >> y TypeError: unsupported operand type(s) for >>: 'float' and 'list'

The result of incompatible addition is a `TypeError`

. You can fix it by using only compatible data types for the in-place bitwise right-shift operation.

Can you use the bitwise right-shift operator on custom objects? Yes!

## Python In-Place Bitwise Right-Shift Magic Method

To use the in-place bitwise right-shift operator `>>=`

on custom objects, you need to define the `__irshift__()`

method (*“dunder method”, “magic method”*) that takes two arguments `self`

and `other`

, updates the first argument `self`

with the result of the operation, and returns the updated object.

In the following code, you combine two `Data`

objects using the in-place right-shift operation:

class Data: def __init__(self, data): self.data = data def __irshift__(self, other): self.data >>= other.data return self x = Data(8) y = Data(2) x >>= y print(x.data) # 2

You can see that the content of the first operand is updated as a result of the in-place bitwise right-shift operation.

## Python In-Place Operators

In-place assignment operators (also called *compound* assignment operators) perform an operation in-place on a variable provided as first operand. They overwrite the value of the first operand variable with the result of the operation when performing the operator without assignment. For example, `x += 3`

is the same as `x = x + 3`

of first calculating the result of `x +3`

and then assigning it to the variable x.

Operator | Name | Short Example | Equivalent Long Example |
---|---|---|---|

`=` | In-place Assignment | `x = 3` | |

`+=` | In-place Addition | `x += 3` | `x = x + 3` |

`-=` | In-place Subtraction | `x -= 3` | `x = x - 3` |

`*=` | In-place Multiplication | `x *= 3` | `x = x * 3` |

`/=` | In-place Division | `x /= 3` | `x = x / 3` |

`%=` | In-place Modulo | `x %= 3` | `x = x % 3` |

`//=` | In-place Integer Division | `x //= 3` | `x = x // 3` |

`**=` | In-place Power | `x **= 3` | `x = x ** 3` |

`&=` | In-place Bitwise And | `x &= 3` | `x = x & 3` |

`|=` | In-place Bitwise Or | `x |= 3` | `x = x | 3` |

`^=` | In-place Bitwise XOR | `x ^= 3` | `x = x ^ 3` |

`>>=` | In-place Bitwise Shift Right | `x >>= 3` | `x = x >> 3` |

<<= | In-place Bitwise Shift Left | `x <<= 5` | `x = x << 5` |