To convert an integer i
to a string with leading zeros so that it consists of 5
characters, use the format string f'{i:05d}'
. The d
flag in this expression defines that the result is a decimal value. The str(i).zfill(5)
accomplishes the same string conversion of an integer with leading zeros.
Challenge: Given an integer number. How to convert it to a string by adding leading zeros so that the string has a fixed number of positions.
Example: For integer 42, you want to fill it up with leading zeros to the following string with 5 characters: '00042'
.
In all methods, we assume that the integer has less than 5 characters.
Method 1: Format String
The first method uses the format string feature in Python 3+ called f-strings or replacement fields.
💡 Info: In Python, f-strings allow for the embedding of expressions within strings by prefixing a string with the letter "f"
or "F"
and enclosing expressions within curly braces {}
. The expressions within the curly braces in the f-string are evaluated, and their values are inserted into the resulting string. This allows for a concise and readable way to include variable values or complex expressions within string literals.
The following f-string converts an integer i
to a string while adding leading zeros to a given integer:
# Integer value to be converted i = 42 # Method 1: Format String s1 = f'{i:05d}' print(s1) # 00042
The code f'{i:05d}'
places the integer i
into the newly created string. However, it tells the format language to fill the string to 5
characters with leading '0'
s using the decimal system.
This is the most Pythonic way to accomplish this challenge.
Method 2: zfill()
Another readable and Pythonic way to fill the string with leading 0s is the string.zfill()
method.
# Method 2: zfill() s2 = str(i).zfill(5) print(s2) # 00042
The method takes one argument and that is the number of positions of the resulting string. Per default, it fills with 0s.
You can check out the following video tutorial from Finxter Adam:
Method 3: List Comprehension
Many Python coders don’t quite get the f-strings and the zfill()
method shown in Methods 2 and 3. If you don’t have time learning them, you can also use a more standard way based on string concatenation and list comprehension.
# Method 3: List Comprehension s3 = str(i) n = len(s3) s3 = '0' * (5-len(s3)) + s3 print(s3)
You first convert the integer to a basic string. Then, you create the prefix of 0
s, you need to fill it up to n=5
characters and concatenate it to the integer’s string representation. The asterisk operator creates a string of 5-len(s3)
zeros here.
If you want to learn how to add trailing zeros instead of leading zeros, check out this article on the Finxter blog.
Where to Go From Here?
Enough theory. Let’s get some practice!
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