The min()
function returns the minimum of the provided arguments. As arguments, you can either pass a number of comma-separated values, or a single iterable. An optional key
function argument allows you to customize the calculation of the minimum by explicitly defining the weight of each value in the iterable that is used as a basis of comparison.
Here’s an example:
>>> min(1, 2, 3) 1 >>> min(1, 2, 3, key = lambda x: -x) 3
Syntax min()
Syntax:
min(iterable, *[, key, default])
min(arg1, arg2, *args[, key])
Argument | iterable | An iterable of elements. |
Argument | arg1, arg2 , *args | At least two arguments —but more are allowed. |
Argument | key | Key function that associates a numerical value to each element that is used as the basis of comparison. |
Return Value | object | Returns the minimum element from the arguments |
Return Value min()
The min()
function returns the minimum among at least two arguments.
Summary
The min()
function returns the maximum of the provided arguments.
>>> min(1, 2, 3) 1
- You can pass either an arbitrary number of values, comma-separated (see before), or
- An iterable as arguments (see next).
>>> min([1, 2, 3]) 1
An optional key
function argument allows you to customize the calculation of the minimum by explicitly defining the weight of each value in the iterable that is used as a basis of comparison.
>>> min([1, 2, 3], key = lambda x: -x) 3
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