Problem Formulation
- Given a floating point number
x = 123.456. - How to print the number without decimal remainder?
x = 123.456 print(x) # Desired output: 123 # Real output: 123.456
Solution 1: int()
Python’s built-in function int(x) converts any float number x to an integer by truncating it towards 0. For example, positive int(1.999) will be truncated to 1 and negative int(-1.999) to -1.
>>> int(123.456) 123 >>> int(-123.456) -123
To boost your skills, feel free to watch my explainer video on the int() function next:
Solution 2: round()
Python’s built-in function round(x), when called with a single float argument x, converts the float to an integer by rounding it up and down to the next integer. For example, int(1.999) will be rounded to 2 and int(-1.999) to -2.
>>> round(123.456) 123 >>> round(-123.456) -123
To boost your skills, feel free to watch my explainer video on the round() function next:
Solution 3: Print Decimal and Non-Decimal Parts Separately
Given a string representing a floating point number, you can print the parts before and after the decimal point by splitting the string on the decimal point and converting the two parts to integers by using the int() built-in function in a list comprehension statement.
x = '123.456'
num, decimal = [int(part) for part in x.split('.')]
print(num)
# 123
print(decimal)
# 456
This snippet builds on four Python concepts you need to understand first:
int()function,- multiple assignment,
- list comprehension, and
string.split()method.
Let’s explore the most important one, the list comprehension statement, in the following video!
Where to Go From Here?
Enough theory. Let’s get some practice!
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