>>> s = {'Alice', 'Bob', 'Carl'} >>> t = {'Alice', 'Bob'} >>> s.issuperset(t) True

Another minimal Harry Potter example:

>>> hogwarts = {'Ron', 'Harry', 'Hermione', 'Dumbledore', 'Parvati', 'Malfoy'} >>> gryffindors = {'Ron', 'Harry', 'Hermione'} >>> hogwarts.issuperset(gryffindors) True

## Syntax

set.issuperset(set)

## Return Value of set.issuperset()

## Advanced Examples set.issuperset()

We start with a simple and trivial example:

>>> {'Alice', 'Bob'}.issuperset({'Alice'}) True

?Β Can you also pass a list as an argument to the `set.issuperset()`

method? The answer is yes—the method takes any iterable.

>>> {'Alice', 'Bob'}.issuperset(['Alice']) True

A set is the superset of itself.

>>> s = {1, 2, 3} >>> s.issuperset(s) True

This also means that two empty sets are the supersets of each other.

>>> set().issubset(set()) True

Can we pass multiple set arguments into the `set.issuperset()`

method? No! It only takes one argument.

>>> {1, 2, 3}.issuperset({1, 2}, {3}) Traceback (most recent call last): File "<pyshell#4>", line 1, in <module> {1, 2, 3}.issuperset({1, 2}, {3}) TypeError: issuperset() takes exactly one argument (2 given)

To fix this `TypeError`

, pass only one set argument into the `set.issuperset()`

method.

## What is the Time Complexity of set.issuperset() in Python?

import matplotlib.pyplot as plt import time sizes = [i * 10**5 for i in range(50)] runtimes = [] for size in sizes: s = set(range(size)) t = set(range(0, size, 2)) # Start track time ... t1 = time.time() s.issuperset(t) t2 = time.time() # ... end track time runtimes.append(t2-t1) plt.plot(sizes, runtimes) plt.ylabel('Runtime (s)') plt.xlabel('Set Size') plt.show()

## Other Python Set Methods

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