🍎Summary: Use Python’s built-in split function to split a given string into a list substrings. Other methods include using the regex library and the map function.
Minimal Example
text = "Python Java Golang"
# Method 1
print(text.split())
# Method 2
import re
print(re.split('\s+',text))
# Method 2.1
print(re.findall('\S+', text))
# Method 3
li = list(map(str.strip, text.split()))
res = []
for i in li:
for j in i.split():
res.append(j)
print(res)
# OUTPUTS: ['Python', 'Java', 'Golang']
Problem Formulation
📜Problem: Given a string containing numerous substrings. How will you split the string into a list of substrings?
Let’s understand the problem with the help of an example.
Example
# Input text = "word1 word2 word3 word4 word5" # Output ['word1', 'word2', 'word3', 'word4', 'word5']
Method 1: Using strip
Approach: Use the split("sep") function where sep is the specified separator. In our case the separator is a space. Hence, you do not need to pass any separator to the function as whitespaces are considered to be default separators for the split function. Therefore, whenever a space occurs the string will be split and the substring will be stored in a list.
Code:
text = "word1 word2 word3 word4 word5" print(text.split()) # ['word1', 'word2', 'word3', 'word4', 'word5']
Method 2: Using re.split
The re.split(pattern, string) method matches all occurrences of the pattern in the string and divides the string along the matches resulting in a list of strings between the matches. For example, re.split('a', 'bbabbbab') results in the list of strings ['bb', 'bbb', 'b'].
Approach: Use thr re.split('\s+',text) method, where text is the given string and ‘\s+‘ returns a match whenever it finds a space in the string.Therefore, on every occurrence of a space the string will be split.
Code:
import re
text = "word1 word2 word3 word4 word5"
print(re.split('\s+',text))
# ['word1', 'word2', 'word3', 'word4', 'word5']
🚀Related Read: Python Regex Split
Method 3: Using re.findall
The re.findall(pattern, string) method scans string from left to right, searching for all non-overlapping matches of the pattern. It returns a list of strings in the matching order when scanning the string from left to right.
🚀Related Read: Python re.findall() – Everything You Need to Know
Approach: Use thr re.findall('\S+',text) method, where text is the given string and ‘\S+‘ returns a match whenever it finds a normal character in the string except whitespace. Therefore, all the non-whitespace characters will be grouped together until the script encounters a space. On the occurrence of a space, the string will be split and the next group of characters that do not include a space will be searched.
Code:
import re
text = "word1 word2 word3 word4 word5"
print(re.findall('\S+', text))
# ['word1', 'word2', 'word3', 'word4', 'word5']
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Method 4: Using map
Prerequisite: The map() function transforms one or more iterables into a new one by applying a “transformator function” to the i-th elements of each iterable. The arguments are the transformator function object and one or more iterables. If you pass n iterables as arguments, the transformator function must be an n-ary function taking n input arguments. The return value is an iterable map object of transformed, and possibly aggregated, elements.
🚀Related Read: Python map() — Finally Mastering the Python Map Function [+Video]
Approach: Use the map function such that the iterable is the split list of substrings. This is the second argument of the map method. Now each item of this list will be passed to the strip method which eliminates the trailing spaces if any and then returns a map object containing the split substrings. You can convert this map object to a list using the list constructor.
Code:
text = "word1 word2 word3 word4 word5"
li = list(map(str.strip, text.split()))
res = []
for i in li:
for j in i.split():
res.append(j)
print(res)
# ['word1', 'word2', 'word3', 'word4', 'word5']
Exercise
Problem: Given a string containing numerous substrings separated by commas and spaces. How will you extract the substrings and store them in a list? Note that you have to eliminate the whitespaces as well as the commas.
# Input text = "One, Two, Three" # Output ['One', 'Two', 'Three']
🔎Hint: Python | Split String by Comma and Whitespace
Solution:
text = "One, Two, Three"
print([x.strip() for x in text.split(',')])
# ['One', 'Two', 'Three']
Conclusion
With that, we come to the end of this tutorial. I hope the methods discussed in this article have helped you and answered your queries. Please stay tuned and subscribe for more solutions and discussions in the future.
Happy learning!🐍
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