In Python, the equivalent of `&&`

(logical-and) in programming languages such as C++ or Java in an if-statement is `and`

. Using `&&`

will raise a SyntaxError, so use `and`

instead!

**Overview**

**Problem: **What is the equivalent of &&(logical-and) in Python?

**Example: **Let’s have a look at the following example:

num_1 = [11, 21, 31, 41, 51] num_2 = [15, 16, 17, 18, 19, 20, 21] if len(num_1) % 2 == 0 && len(num_2) % 2 == 0: print("The lists has even number of elements") elif len(num_1) % 2 != 0 && len(num_2) % 2 != 0: print("odd numbers") else: print("mix of odd and even numbers")

**Output:** You will get the following error inside the “if” statement.

if len(num_1) % 2 == 0 && len(num_2) % 2 == 0: ^ SyntaxError: invalid syntax

Well! This can be really frustrating. You have got the logic right, yet there’s an error. Why? The answer is not as difficult as you might have thought.

We encountered the syntax error because of the usage of ** &&** operator in our code. Python does not have the provision for the

**operator. Hence, when Python comes across “**

`&&`

`&&`

” in the program, it is unable to identify the operator and deems it as invalid. Therefore, we see the*Syntax Error.*Β

π **Instant Fix: **Replace the `&&`

operator with ** and**, which will solve the issue.

**Logical Operators in Python**

**What are Operators in Python?** Operators are the special symbols that are used to perform operations on the variables and values. They carry out arithmetic and logical computations.

The **logical operators** in Python are used on conditional statements, i.e, either `True`

or `False`

. The three logical operations are:

- (i) Logical AND
- (ii) Logical OR
- (iii) Logical NOT.

Operator | Description | Example |
---|---|---|

`and` | Returns `True` if both operands are `True` , and `False` otherwise. | `(True and True) == True` |

`or` | Returns `True` if one operand is `True` , and otherwise it returns `False` . | `(False or True) == True` |

`not` | Returns `True` if the single operand is `False` , otherwise returns `False` . | `(not True) == False` |

**Logical AND**

The Logical AND operator is used to return `True`

if both operands are `True`

. However, if any one of the two operands is `False`

, then it returns False.Β

Let’s look at an example to understand this:

# functioning of Logical and operator val_1 = -5 val_2 = 10 if val_1 > 0 and val_2 > 0: print("The numbers are positive numbers") elif val_1 < 0 and val_2 < 0: print("The numbers are negative numbers") else: print("One of the given numbers is positive while the other number is negative!")

**Output:**

One of the given numbers is positive while the other number is negative!

Now let’s get back to our first example. When we replace the ** &&** with

**the error gets solved.**

`and`

**Solution:**

val_1 = [11, 21, 31, 41, 51] val_2 = [15, 16, 17, 18, 19, 20, 21] # Using logical and if len(val_1) % 2 == 0 and len(val_2) % 2 == 0: print("List has Even number of elements.") elif len(val_1) % 2 != 0 and len(val_2) % 2 != 0: print("List has odd number of elements.") else: print("List 1 has Odd number of elements while list 2 has even number of elements!")

**Output:**

List has odd number of elements.

Hence, **“ and” is Python’s equivalent of && (logical-and) in an if-statement**. In the same way, we cannot use the

**Β operator in Python as it is not valid. We have to use its equivalent logical or which is denoted by “**

`||`

**” in Python.**

`or`

**Logical OR**

The Logical OR operator is used to return `True`

if either of the operands is `True`

. It returns `false`

only if both of the operands are `False`

.

Let’s look at one example to understand this:

# functioning of Logical or operator num_1 = -5 num_2 = -10 num_3 = 8 print("For the first two numbers:") if num_1 > 0 or num_2 > 0: print("Either of the numbers is positive") else: print("Numbers are negative numbers") print("For the last two numbers") if num_2 > 0 or num_3 > 0: print("Either of the numbers is positive") else: print("Numbers are negative numbers")

**Output:**

For the first two numbers: Numbers are negative numbers For the last two numbers Either of the numbers is positive

**The Python Advantage of Logical Operators**

Python is a way more user-friendly language. While you have to use symbols like “`&&`

” and “`||`

” in some other languages like C++ and Java, Python makes life easy for you by providing direct words like “`and`

” , “`or`

“, etc which make more sense and resemble normal English.

Further, logical operators (in most languages) have the advantage of being short-circuited. This means that it first evaluates the first operand, and if only the first operand defines the result, then the second operand is not evaluated at all.

Look at the following example:

def check(v): print(v) return v temp = check(False) and check(True) # False

In the above example, only one print statement is executed, i.e., Python evaluated only the first operand. As we know the `AND`

operator returns `False`

, if one of the operands is `False`

. The first operand, in this case, was `False`

hence Python did not evaluate the second operand.Β Β

However, let’s look at a different situation-

def check(v): print(v) return v print("Output for first call: ") temp = check(True) and check(True) print("Output for the second call:") temp = check(True) and check(False)

**Output:**

Output for first call: True True Output for the second call: True False

In the above example, as the first operand is `True`

we cannot determine the result for the “`and`

” operation. Hence, Python needs to evaluate the second operand as well.

It works similarly for the OR operand where Python first checks the first operand.Β As we know, the OR logical operator returns `False`

only if both of the operands are `False`

. So, if the first operand is `False`

only then it evaluates the second operand. However, if the first operand is `True`

, it concludes that the output is `True`

without even checking the second operand.

π**Bonus: **Pseudocode for AND and OR function is as follows:

def and(oper1, oper2): left = evaluate(oper1) if bool(left): return evaluate(oper2) else: return left def or(oper1, oper2): left = evaluate(oper1) if bool(left): return left else: return evaluate(oper2)

**Related Video**

**Related Questions**

Here are some questions and their quick solution, which are frequently asked along with the problem discussed in this article –

**How to use “and” operator to check equality between strings?**

**Solution:**

word = "MADAM" if word and word[::-1]: print("PALINDROME!") # PALINDROME

**What is the replacement for the switch statement in Python?**

**Solution:**

def switch(x): return { "1": 'One', "2": 'Two' }.get(x, "wrong entry!") n = input("Enter your Choice: ") print(switch(n))

**Output:**

```
Enter your Choice: 1
One
```

**Conclusion**

In this article, we learned about the logical operators and** Python’s equivalent of && (logical-and) and || (logical-or) in an if-statement.** I hope this article has helped you. Please stay tuned and

**subscribe**for more such articles.

**Recommended Read: Python And Operator**